A random sample of n=1400 registered voters and found that 720 would vote for the Republican candidate in a state senate race. Let p represent the proportion of registered voters who would vote for the Republican candidate.Consider testingH0:p=.50Ha:p>.50(a) The test statistic is z =(b) Regardless of what you acutally computed, suppose your answer to part (a) was z = 1.28. Using this z, p-value =

Answer:1.070,0.1003Step-by-step explanation:Given that a random sample of n=1400 registered voters and found that 720 would vote for the Republican candidate in a state senate race. p =  the proportion of registered voters who would vote for the Republican candidate.Sample proportion = [tex]\frac{720}{1400} =0.5143[/tex]Hypotheses are:[tex]H_0:p=0.50\\H_a:p>0.50[/tex](Right tailed test )p difference = [tex]0.5143-0.5=0.0143[/tex]Assuming null hypothesis to be true, Std error = [tex]\sqrt{\frac{0.5(0.5)}{1400} } \\=0.0134[/tex]a) Test statistic Z = p difference/std error = 1.070b) When z =1.28, p value = 0.100273