Select the two values of x that are roots of this equation.2x2 + 11x+15= 0
Accepted Solution
A:
Answer:The two values of x are -2.5 and -3Step-by-step explanation:we have[tex]2x^{2}+11x+15=0[/tex]The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]a=2\\b=11\\c=15[/tex]
substitute in the formula
[tex]x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}[/tex]
[tex]x=\frac{-11(+/-)\sqrt{1}} {4}[/tex]
[tex]x=\frac{-11(+/-)1} {4}[/tex]
[tex]x_1=\frac{-11(+)1} {4}=-2.5[/tex]
[tex]x_2=\frac{-11(-)1} {4}=-3[/tex]
thereforeThe two values of x are -2.5 and -3