2. You throw a softball straight up into the air at a velocity of 30 feet per second. You release the softball at a height of 5.8 feet and catch it when it falls back to a height of 6.2 feet. Use the position equation to write a mathematical model for the height of the softball

Answer:[tex]-16t^2+30t+5.8[/tex]Step-by-step explanation:We are given that Initial velocity=30 ft/sInitial position=[tex]s_0=5.8 ft[/tex]We have to write a mathematical model for height of the softball by using the position equation The position equation on Earth's surface is given by [tex]h(t)=-16t^2+v_0t+s_0[/tex]Where [tex]v_0=[/tex] Initial velocity[tex]s_0[/tex]=Initial positionSubstitute the values in the equation then, we get [tex]h(t)=-16t^2+30t+5.8[/tex]Hence, the mathematical model for height of the softball is given by [tex]-16t^2+30t+5.8[/tex]