Select the two values of x that are roots of this equation.2x+11x+15= 0

Answer:The roots of the equation are x=-3 and x=-2.5Step-by-step explanation:The correct quadratic equation is2x^2+11x+15=0we know thatThe formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to [tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex] in this problem we have [tex]2x^{2} +11x+15=0[/tex]  so [tex]a=2\\b=11\\c=15[/tex] substitute in the formula [tex]x=\frac{-11(+/-)\sqrt{11^{2}-4(2)(15)}} {2(2)}[/tex] [tex]x=\frac{-11(+/-)\sqrt{121-120}} {4}[/tex] [tex]x=\frac{-11(+/-)\sqrt{1}} {4}[/tex] [tex]x=\frac{-11(+/-)1} {4}[/tex] [tex]x_1=\frac{-11(+)1}{4}=-2.5[/tex] [tex]x_2=\frac{-11(-)1}{4}=-3[/tex] thereforeThe roots of the equation are x=-3 and x=-2.5